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PHP Post Request mit File Upload

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Torben Brodt

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Lexicon articles: 104

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Sunday, October 23rd 2011, 10:13am

Tags

formular, fsockopen, Upload

Abstract

In diesem Tutorial erfahrt ihr, wie ihr File Uploads mit PHP an ein Formular schickt.

Article

Wenn ihr von eurem Webserver eine Datei an ein Upload Script schicken wollt, bietet euch PHP keine Standardfunktionen.\\
Eine Funktion dazu reiche ich euch hiermit nach.

Das passende Formular auf Empfängerseite würde grob gesehen folgendermaßen aussehen:

HTML Code

 
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<form>
	<input type="text" name="var1" />
	<input type="text" name="var2" />
	<input type="file" name="inputname" />
	<input type="submit" />
</form>


Hier nun das Script auf Senderseite:

PHP Quellcode

 
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<?php
function postToHost($host, $port, $path, $postdata = array(), $filedata = array()) {
	$data = "";
	$boundary = "---------------------".substr(md5(rand(0,32000)),0,10);
	$fp = fsockopen($host, $port);
 
	fputs($fp, "POST $path HTTP/1.0\n");
	fputs($fp, "Host: $host\n");
	fputs($fp, "Content-type: multipart/form-data; boundary=".$boundary."\n");
 
	// Ab dieser Stelle sammeln wir erstmal alle Daten in einem String
	// Sammeln der POST Daten
	foreach($postdata as $key => $val){
	    $data .= "--$boundary\n";
	    $data .= "Content-Disposition: form-data; name=\"".$key."\"\n\n".$val."\n";
	}
 
	// Sammeln der FILE Daten
	if($filedata) {
		$data .= "--$boundary\n";
		$data .= "Content-Disposition: form-data; name=\"".$filedata['name']."\"; filename=\"".$filedata['name']."\"\n";
		$data .= "Content-Type: ".$filedata['type']."\n";
		$data .= "Content-Transfer-Encoding: binary\n\n";
		$data .= $filedata['data']."\n";
		$data .= "--$boundary--\n";
	}
 
	// Senden aller Informationen
	fputs($fp, "Content-length: ".strlen($data)."\n\n");
	fputs($fp, $data);
 
	// Auslesen der Antwort
	while(!feof($fp)) {
		$res .= fread($fp, 1);
	}
	fclose($fp);
 
	return $res;
}
 
$postdata = array('var1'=>'test', 'var2'=>'test');
$filedata = array(
	'name' => 'inputname',
	'filename' => 'image2.jpg',
	'type' => 'image/jpeg',
	'data' => file_get_contents('/home/easycoding/image2.jpg')
);
 
echo '<pre>'.postToHost ("localhost", 80, "/test3.php", $postdata, $filedata).'</pre>';
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